topic badge
AustraliaVIC
VCE 11 General 2023

10.03 Perimeter

Lesson

Perimeters

The perimeter is the distance around a two dimensional shape. To find the perimeter of any polygon (straight sided shape) add all the lengths of the sides, ensuring all lengths are written in the same unit.

Perimeter is a measure of length, so different units of measure could be used to measure the perimeter of different sized objects. Millimetres could be used to measure the perimeter of a SIM card, centimetres to measure the perimeter of a wallet, metres to measure the perimeter of a room and kilometres to measure the perimeter of a town.

If no particular unit for the context or question is given it is also good mathematical practice to use the word 'units'.

Here is a scalene triangle. To find the perimeter add the three side lengths. Notice that all sides are measured using the same units.

A scalene triangle with side lengths of 6 centimetres, 12 centimetres, and 14 centimetres.
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 14 + 12 + 6Add the lengths of the sides
\displaystyle =\displaystyle 32\text{ cm}Evaluate

Here is a rectangle. Recall that rectangles have opposite sides of equal length.

A rectangle with measurements of 6 millimetres on the shorter side and 13 millimetres on the longer side.
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 2\times (13+6)Add the length and the width
\displaystyle =\displaystyle 2 \times 19Find the sum in the brackets
\displaystyle =\displaystyle 38\text{ mm}Evaluate

A square has 4 sides of the same length, so the perimeter of a square will be 4 times one of the side lengths.

A square with side length of 7.4 centimetres.
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 4 \times 7.4Multiply 4 by the length
\displaystyle =\displaystyle 29.6\text{ cm}Evaluate

All perimeters can be found by traveling around the shape, adding up one side at a time.

Here is a trapezium. To find its perimeter add the side lengths.

A trapezium with side lengths of 1.3 metres, 1.2 metres, 2.7 metres, and 2.4 metres.
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 1.3+1.2+2.7+2.4Add the lengths of the sides
\displaystyle =\displaystyle 7.6\text{ m}Evaluate

Also keep in mind the ability to construct simple rules for other shapes as necessary, and to group together sides of the same lengths.

A composite shape with 5 different side lengths in metres. Ask your teacher for more information.
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 3\times 1+2\times 3.6+1.4+1.5+3.45
\displaystyle =\displaystyle 3+7.2+2.9+3.45
\displaystyle =\displaystyle 16.55\text{ m}

Examples

Example 1

Find the perimeter of the shaded region shown, where edges are 1 unit in length each.

A grid with 14 shaded squares that made a larger shape. Ask your teacher for more information.
Worked Solution
Create a strategy

Count the unit edges around the shaded region.

Apply the idea

\text{Perimeter}=20\text{ units}

Example 2

Find the perimeter of the figure shown.

A hexagon with 6 different side lengths in centimetres. Ask your teacher for more information.
Worked Solution
Create a strategy

The perimeter of a figure is the sum of all of its sides.

Apply the idea
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 10 + 7 + 9 + 11 + 9 + 8Add the sides
\displaystyle =\displaystyle 54 \text{ cm}Evaluate
Idea summary

The perimeter is the distance around a two dimensional shape. To find the perimeter of any polygon (straight sided shape) add all the lengths of the sides, ensuring all lengths are written in the same unit.

Circumference

The perimeter of a circle, the circumference, can be used to find the perimeter of composite shapes that involve full circles, or semicircles.

A composite shape, made up of a semicircle and a rectangle. Ask your teacher for more information.

The circumference C of a circle is given by: \\C=2\pi r=\pi d, where r is the radius and d is the diameter of the circle.

This is a composite shape, made up of a semicircle and a rectangle. Although, we are missing one side of the rectangle, we can use the circumference of a circle, and halve this, to find the length of the rounded edge.

We have 3 straight sides, two with length 4 cm and one with length 8.4 cm. The sum of these lengths is equal to:

2 \times 4 + 8.4 = 16.4\text{ cm}

Lastly we have a semicircle of radius \dfrac{8.4}{2}=4.2\text{ cm}. So the length of the rounded edge is equal to:

\dfrac{2\pi \times 4.2}{2} = 4.2\pi\text{ cm}

In total, the perimeter is:

\text{Perimeter}=16.4 + 4.2\pi \approx 29.6 \text{ cm} (1 \text{d.p.})

Examples

Example 3

Find the circumference of the circle shown, correct to two decimal places.

A circle with a radius of 8 centimeters
Worked Solution
Create a strategy

The circumference of the circle can be found using the formula: C=2\pi r.

Apply the idea
\displaystyle C\displaystyle =\displaystyle 2\times \pi \times 8Substitute r=8
\displaystyle =\displaystyle 50.27\text{ cm}Evaluate

Example 4

Find the perimeter of the shape (shaded) shown, correct to two decimal places.

A composite shape composed of two semicircles in the two sides of the square. Ask your teacher for more information.
Worked Solution
Create a strategy

We need to add the lengths of the borders for the perimeter.

Apply the idea
\displaystyle \text{Perimeter}\displaystyle =\displaystyle 37.0 + 37.0 + \dfrac{37.0}{2}\pi + \dfrac{37.0}{2}\piSubstritute r=37.0
\displaystyle =\displaystyle 37.0 + 37.0 + 18.5\pi + 18.5\piEvaluate the division
\displaystyle =\displaystyle 37.0 + 37.0 + 116.24Add and simplify terms with \pi
\displaystyle =\displaystyle 190.24 \text{ units}Evaluate
Idea summary

The formula for circumference of a circle is :

\displaystyle C=\pi d
\bm{C}
is the cirumference
\bm{d}
is the diameter

and because the diameter is twice the radius, we can also write the formula as

\displaystyle C=2\pi r
\bm{C}
is the circumference
\bm{r}
is the radius

Arc lengths and sectors

An arc of a circle is a curved line formed from part of the circumference of the circle. The length of an arc is called the arc length, 1.

A sector is a shaped formed from part of a circle, where the sector's boundary or perimeter is formed by two radii and an arc.

Finding the perimeter of a sector involves first calculating the arc length, then adding on the lengths of the two radii.

The image shows three examples of sectors. Ask your teacher for more information.

Note that a quarter of a circle, is sometimes called a quadrant, and half of a circle is usually called a semicircle.

Examples

Example 5

Find the perimeter of the sector equal to \dfrac{1}{4} of a circle with radius 6.5 cm. Round to one decimal place.

Worked Solution
Create a strategy

We need to first find the value of arc lenght (l) and then substitute it to the formula: \\\text{Perimeter}=\text{arc length}+2\times \text{radius}.

Apply the idea

To find the arc length:

\displaystyle l\displaystyle =\displaystyle \dfrac{1}{4} \times 2\pi rWrite the formula
\displaystyle =\displaystyle \dfrac{1}{4} \times 2\times \pi \times 6.5Substitute r=6.5
\displaystyle =\displaystyle 3.25\piEvaluate and leave answer in terms of \pi

To find the perimeter:

\displaystyle \text{Perimeter}\displaystyle =\displaystyle l + 2 \times rWrite the formula
\displaystyle =\displaystyle 3.25\pi + 2 \times 6.5Susbstitute l=3.25\pi,\,r=6.5
\displaystyle =\displaystyle 23.2 \text{ cm}Evaluate and round to 1 decimal place

Example 6

What is the perimeter of a semicircle with diameter 8 cm, correct to two decimal places?

Worked Solution
Create a strategy

We can use the circumference formula: C = \pi \times D, then multiply it by \dfrac{1}{2} since it is semicircle, and the add the diameter to find the perimeter.

Apply the idea
\displaystyle \text{Perimeter}\displaystyle =\displaystyle \pi \times 8 \times \dfrac{1}{2} + 8Substitute D=8
\displaystyle =\displaystyle 12.57 + 8Evaluate the multiplication
\displaystyle =\displaystyle 20.57\text{ cm}Evaluate

Example 7

A circle with radius 4\text{ cm} has been drawn with a dashed line. A sector is outlined with a filled line.

A circle is drawn with dashed line. A sector has a radius of 4 centimetres, and a central angle marked with a right angle.
a

Find the exact circumference of the whole circle.

Worked Solution
Create a strategy

We can use the formula for circumference: C=2\pi r

Apply the idea
\displaystyle C\displaystyle =\displaystyle 2\pi \times 4Substitute r=4
\displaystyle =\displaystyle 8\pi\text{ cm}Simplify
b

Find the exact length of the arc of the sector.

Worked Solution
Create a strategy

The sector is a quarter of the circle, so we can use the formula for the arc length of the sector: l= \dfrac{1}{4} \times 2\pi r .

Apply the idea

We know the sector is a quarter of the circle because of the right-angle marking at the centre.

\displaystyle l\displaystyle =\displaystyle \dfrac{1}{4} \times 2\times \pi \times 4Substitute r=4
\displaystyle =\displaystyle 2\pi\text{ cm}Simplify
c

Find the perimeter of the sector. Round the answer to two decimal places.

Worked Solution
Create a strategy

The perimeter of a sector made up of the arc length, l, and two radii, 2r. So we add these length together.

Apply the idea
\displaystyle \text{Perimeter}\displaystyle =\displaystyle l + 2rAdd the arc and the radii
\displaystyle =\displaystyle 2\pi + 2 \times 4Substitute l and r
\displaystyle =\displaystyle 14.28 \text{ cm}Evaluate and round
Idea summary

An arc of a circle is a curved line formed from part of the circumference of the circle. The length of an arc is called the arc length, 1.

A sector is a shaped formed from part of a circle, where the sector's boundary or perimeter is formed by two radii and an arc.

Outcomes

U2.AoS4.5

the perimeter and areas of triangles (using several methods based on information available), quadrilaterals, circles and composite shapes, including arcs

U2.AoS4.11

calculate the perimeter and areas of triangles (calculating the areas of triangles in practical situations using the rules A=1/2 bh, A=1/2 ab sin(c) or A=\sqrt{s(s-a)(s-b)(s-c)} where s=(a+b+c)/2

U2.AoS4.12

use quadrilaterals, circles and composite shapes including arcs and sectors in practical situations

U2.AoS4.13

calculate the perimeter, areas, volumes and surface areas of solids (spheres, cylinders, pyramids and prisms and composite objects) in practical situations, including simple uses of Pythagoras’ in three dimensions

What is Mathspace

About Mathspace